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12p^2-11p-12=0
a = 12; b = -11; c = -12;
Δ = b2-4ac
Δ = -112-4·12·(-12)
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{697}}{2*12}=\frac{11-\sqrt{697}}{24} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{697}}{2*12}=\frac{11+\sqrt{697}}{24} $
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